A rectangular loop with a sliding connector of length
is situated in uniform magnetic field perpendicular to plane of loop. The magnetic induction is
and resistance of connector (R) is
. The sides AB and CD have resistances
and
respectively. Find the current in the connector during its motion with constant velocity one meter/second.

Text Solution
Verified by ExpertsThe correct answer is:
B
Emf induced in rod = BLv


now applying KVL in mesh (i)


In mesh-(ii);



From this we get
.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A square loop of side a and resistance R is moved in the region of uniform magnetic field B (loop r…
There is a uniform magnetic field B normal to the xy plane. A conductor ABC has length AB , parall…
A square coil ABCD is placed in x‐y plane with its center at origin. A long straight wire, passing …
A rectangular coil of single turn, having area A, rotates in a uniform magnetic field B at an angul…
A ring of resistance , radius and 100 turns is rotated at a rate 100 revolutions per second about…
An equilateral triangular loop of uniform specific resistivity having some resistance is pulled wi…